Integrand size = 30, antiderivative size = 397 \[ \int x \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (i+j x)^m\right )\right ) \, dx=\frac {a g i m x}{2 j}+\frac {b d f n x}{2 e}-\frac {3 b d g m n x}{4 e}-\frac {3 b g i m n x}{4 j}+\frac {1}{4} b g m n x^2+\frac {b d^2 g m n \log (d+e x)}{4 e^2}+\frac {b g i m (d+e x) \log \left (c (d+e x)^n\right )}{2 e j}-\frac {1}{4} g m x^2 \left (a+b \log \left (c (d+e x)^n\right )\right )+\frac {b g i^2 m n \log (i+j x)}{4 j^2}-\frac {g i^2 m \left (a+b \log \left (c (d+e x)^n\right )\right ) \log \left (\frac {e (i+j x)}{e i-d j}\right )}{2 j^2}+\frac {b d g n (i+j x) \log \left (h (i+j x)^m\right )}{2 e j}-\frac {1}{4} b n x^2 \left (f+g \log \left (h (i+j x)^m\right )\right )-\frac {b d^2 n \log \left (-\frac {j (d+e x)}{e i-d j}\right ) \left (f+g \log \left (h (i+j x)^m\right )\right )}{2 e^2}+\frac {1}{2} x^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (i+j x)^m\right )\right )-\frac {b g i^2 m n \operatorname {PolyLog}\left (2,-\frac {j (d+e x)}{e i-d j}\right )}{2 j^2}-\frac {b d^2 g m n \operatorname {PolyLog}\left (2,\frac {e (i+j x)}{e i-d j}\right )}{2 e^2} \]
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Time = 0.31 (sec) , antiderivative size = 397, normalized size of antiderivative = 1.00, number of steps used = 23, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.300, Rules used = {2489, 45, 2463, 2436, 2332, 2442, 2441, 2440, 2438} \[ \int x \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (i+j x)^m\right )\right ) \, dx=\frac {1}{2} x^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (i+j x)^m\right )\right )-\frac {g i^2 m \log \left (\frac {e (i+j x)}{e i-d j}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{2 j^2}-\frac {1}{4} g m x^2 \left (a+b \log \left (c (d+e x)^n\right )\right )+\frac {a g i m x}{2 j}+\frac {b g i m (d+e x) \log \left (c (d+e x)^n\right )}{2 e j}-\frac {b d^2 n \log \left (-\frac {j (d+e x)}{e i-d j}\right ) \left (f+g \log \left (h (i+j x)^m\right )\right )}{2 e^2}-\frac {b d^2 g m n \operatorname {PolyLog}\left (2,\frac {e (i+j x)}{e i-d j}\right )}{2 e^2}+\frac {b d^2 g m n \log (d+e x)}{4 e^2}+\frac {b d f n x}{2 e}+\frac {b d g n (i+j x) \log \left (h (i+j x)^m\right )}{2 e j}-\frac {b g i^2 m n \operatorname {PolyLog}\left (2,-\frac {j (d+e x)}{e i-d j}\right )}{2 j^2}-\frac {3 b d g m n x}{4 e}-\frac {1}{4} b n x^2 \left (f+g \log \left (h (i+j x)^m\right )\right )+\frac {b g i^2 m n \log (i+j x)}{4 j^2}-\frac {3 b g i m n x}{4 j}+\frac {1}{4} b g m n x^2 \]
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Rule 45
Rule 2332
Rule 2436
Rule 2438
Rule 2440
Rule 2441
Rule 2442
Rule 2463
Rule 2489
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} x^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (i+j x)^m\right )\right )-\frac {1}{2} (g j m) \int \frac {x^2 \left (a+b \log \left (c (d+e x)^n\right )\right )}{i+j x} \, dx-\frac {1}{2} (b e n) \int \frac {x^2 \left (f+g \log \left (h (i+j x)^m\right )\right )}{d+e x} \, dx \\ & = \frac {1}{2} x^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (i+j x)^m\right )\right )-\frac {1}{2} (g j m) \int \left (-\frac {i \left (a+b \log \left (c (d+e x)^n\right )\right )}{j^2}+\frac {x \left (a+b \log \left (c (d+e x)^n\right )\right )}{j}+\frac {i^2 \left (a+b \log \left (c (d+e x)^n\right )\right )}{j^2 (i+j x)}\right ) \, dx-\frac {1}{2} (b e n) \int \left (-\frac {d \left (f+g \log \left (h (i+j x)^m\right )\right )}{e^2}+\frac {x \left (f+g \log \left (h (i+j x)^m\right )\right )}{e}+\frac {d^2 \left (f+g \log \left (h (i+j x)^m\right )\right )}{e^2 (d+e x)}\right ) \, dx \\ & = \frac {1}{2} x^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (i+j x)^m\right )\right )-\frac {1}{2} (g m) \int x \left (a+b \log \left (c (d+e x)^n\right )\right ) \, dx+\frac {(g i m) \int \left (a+b \log \left (c (d+e x)^n\right )\right ) \, dx}{2 j}-\frac {\left (g i^2 m\right ) \int \frac {a+b \log \left (c (d+e x)^n\right )}{i+j x} \, dx}{2 j}-\frac {1}{2} (b n) \int x \left (f+g \log \left (h (i+j x)^m\right )\right ) \, dx+\frac {(b d n) \int \left (f+g \log \left (h (i+j x)^m\right )\right ) \, dx}{2 e}-\frac {\left (b d^2 n\right ) \int \frac {f+g \log \left (h (i+j x)^m\right )}{d+e x} \, dx}{2 e} \\ & = \frac {a g i m x}{2 j}+\frac {b d f n x}{2 e}-\frac {1}{4} g m x^2 \left (a+b \log \left (c (d+e x)^n\right )\right )-\frac {g i^2 m \left (a+b \log \left (c (d+e x)^n\right )\right ) \log \left (\frac {e (i+j x)}{e i-d j}\right )}{2 j^2}-\frac {1}{4} b n x^2 \left (f+g \log \left (h (i+j x)^m\right )\right )-\frac {b d^2 n \log \left (-\frac {j (d+e x)}{e i-d j}\right ) \left (f+g \log \left (h (i+j x)^m\right )\right )}{2 e^2}+\frac {1}{2} x^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (i+j x)^m\right )\right )+\frac {(b g i m) \int \log \left (c (d+e x)^n\right ) \, dx}{2 j}+\frac {(b d g n) \int \log \left (h (i+j x)^m\right ) \, dx}{2 e}+\frac {1}{4} (b e g m n) \int \frac {x^2}{d+e x} \, dx+\frac {\left (b e g i^2 m n\right ) \int \frac {\log \left (\frac {e (i+j x)}{e i-d j}\right )}{d+e x} \, dx}{2 j^2}+\frac {1}{4} (b g j m n) \int \frac {x^2}{i+j x} \, dx+\frac {\left (b d^2 g j m n\right ) \int \frac {\log \left (\frac {j (d+e x)}{-e i+d j}\right )}{i+j x} \, dx}{2 e^2} \\ & = \frac {a g i m x}{2 j}+\frac {b d f n x}{2 e}-\frac {1}{4} g m x^2 \left (a+b \log \left (c (d+e x)^n\right )\right )-\frac {g i^2 m \left (a+b \log \left (c (d+e x)^n\right )\right ) \log \left (\frac {e (i+j x)}{e i-d j}\right )}{2 j^2}-\frac {1}{4} b n x^2 \left (f+g \log \left (h (i+j x)^m\right )\right )-\frac {b d^2 n \log \left (-\frac {j (d+e x)}{e i-d j}\right ) \left (f+g \log \left (h (i+j x)^m\right )\right )}{2 e^2}+\frac {1}{2} x^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (i+j x)^m\right )\right )+\frac {(b g i m) \text {Subst}\left (\int \log \left (c x^n\right ) \, dx,x,d+e x\right )}{2 e j}+\frac {(b d g n) \text {Subst}\left (\int \log \left (h x^m\right ) \, dx,x,i+j x\right )}{2 e j}+\frac {\left (b d^2 g m n\right ) \text {Subst}\left (\int \frac {\log \left (1+\frac {e x}{-e i+d j}\right )}{x} \, dx,x,i+j x\right )}{2 e^2}+\frac {1}{4} (b e g m n) \int \left (-\frac {d}{e^2}+\frac {x}{e}+\frac {d^2}{e^2 (d+e x)}\right ) \, dx+\frac {\left (b g i^2 m n\right ) \text {Subst}\left (\int \frac {\log \left (1+\frac {j x}{e i-d j}\right )}{x} \, dx,x,d+e x\right )}{2 j^2}+\frac {1}{4} (b g j m n) \int \left (-\frac {i}{j^2}+\frac {x}{j}+\frac {i^2}{j^2 (i+j x)}\right ) \, dx \\ & = \frac {a g i m x}{2 j}+\frac {b d f n x}{2 e}-\frac {3 b d g m n x}{4 e}-\frac {3 b g i m n x}{4 j}+\frac {1}{4} b g m n x^2+\frac {b d^2 g m n \log (d+e x)}{4 e^2}+\frac {b g i m (d+e x) \log \left (c (d+e x)^n\right )}{2 e j}-\frac {1}{4} g m x^2 \left (a+b \log \left (c (d+e x)^n\right )\right )+\frac {b g i^2 m n \log (i+j x)}{4 j^2}-\frac {g i^2 m \left (a+b \log \left (c (d+e x)^n\right )\right ) \log \left (\frac {e (i+j x)}{e i-d j}\right )}{2 j^2}+\frac {b d g n (i+j x) \log \left (h (i+j x)^m\right )}{2 e j}-\frac {1}{4} b n x^2 \left (f+g \log \left (h (i+j x)^m\right )\right )-\frac {b d^2 n \log \left (-\frac {j (d+e x)}{e i-d j}\right ) \left (f+g \log \left (h (i+j x)^m\right )\right )}{2 e^2}+\frac {1}{2} x^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (i+j x)^m\right )\right )-\frac {b g i^2 m n \text {Li}_2\left (-\frac {j (d+e x)}{e i-d j}\right )}{2 j^2}-\frac {b d^2 g m n \text {Li}_2\left (\frac {e (i+j x)}{e i-d j}\right )}{2 e^2} \\ \end{align*}
Time = 0.33 (sec) , antiderivative size = 341, normalized size of antiderivative = 0.86 \[ \int x \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (i+j x)^m\right )\right ) \, dx=\frac {b n \log (d+e x) \left (2 e^2 g i^2 m \log (i+j x)+2 g \left (-e^2 i^2+d^2 j^2\right ) m \log \left (\frac {e (i+j x)}{e i-d j}\right )+d j \left (-2 d f j+2 e g i m+d g j m-2 d g j \log \left (h (i+j x)^m\right )\right )\right )+e \left (g i m (-2 a e i+b (e i+2 d j) n) \log (i+j x)+j \left (a e x (2 f j x+g m (2 i-j x))-b n (e x (3 g i m+f j x-g j m x)+d (2 g i m-2 f j x+3 g j m x))+g j x (2 a e x+b n (2 d-e x)) \log \left (h (i+j x)^m\right )\right )+b e \log \left (c (d+e x)^n\right ) \left (-2 g i^2 m \log (i+j x)+j x \left (2 g i m+2 f j x-g j m x+2 g j x \log \left (h (i+j x)^m\right )\right )\right )\right )+2 b g \left (-e^2 i^2+d^2 j^2\right ) m n \operatorname {PolyLog}\left (2,\frac {j (d+e x)}{-e i+d j}\right )}{4 e^2 j^2} \]
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 111.26 (sec) , antiderivative size = 1372, normalized size of antiderivative = 3.46
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\[ \int x \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (i+j x)^m\right )\right ) \, dx=\int { {\left (b \log \left ({\left (e x + d\right )}^{n} c\right ) + a\right )} {\left (g \log \left ({\left (j x + i\right )}^{m} h\right ) + f\right )} x \,d x } \]
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Timed out. \[ \int x \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (i+j x)^m\right )\right ) \, dx=\text {Timed out} \]
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\[ \int x \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (i+j x)^m\right )\right ) \, dx=\int { {\left (b \log \left ({\left (e x + d\right )}^{n} c\right ) + a\right )} {\left (g \log \left ({\left (j x + i\right )}^{m} h\right ) + f\right )} x \,d x } \]
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\[ \int x \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (i+j x)^m\right )\right ) \, dx=\int { {\left (b \log \left ({\left (e x + d\right )}^{n} c\right ) + a\right )} {\left (g \log \left ({\left (j x + i\right )}^{m} h\right ) + f\right )} x \,d x } \]
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Timed out. \[ \int x \left (a+b \log \left (c (d+e x)^n\right )\right ) \left (f+g \log \left (h (i+j x)^m\right )\right ) \, dx=\int x\,\left (a+b\,\ln \left (c\,{\left (d+e\,x\right )}^n\right )\right )\,\left (f+g\,\ln \left (h\,{\left (i+j\,x\right )}^m\right )\right ) \,d x \]
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